-105p^2+24p+8=0

Solution for -105p^2+24p+8=0 equation:

-105p^2+24p+8=0

a = -105; b = 24; c = +8;
Δ = b2-4ac
Δ = 242-4·(-105)·8
Δ = 3936
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{3936}=\sqrt{16*246}=\sqrt{16}*\sqrt{246}=4\sqrt{246}$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-4\sqrt{246}}{2*-105}=\frac{-24-4\sqrt{246}}{-210}
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+4\sqrt{246}}{2*-105}=\frac{-24+4\sqrt{246}}{-210}
$